81=(1/3)^5x-6

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Solution for 81=(1/3)^5x-6 equation: 



81=(1/3)^5x-6

We move all terms to the left:

81-((1/3)^5x-6)=0



Domain of the equation: 3)^5x-6)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+1/3)^5x-6)+81=0

We multiply all the terms by the denominator


-((+1+81*3)^5x-6)=0



We calculate terms in parentheses: -((+1+81*3)^5x-6), so:

(+1+81*3)^5x-6

We add all the numbers together, and all the variables

244^5x-6

Back to the equation:

-(244^5x-6)



We get rid of parentheses

-244^5x+6=0

We move all terms containing x to the left, all other terms to the right

-244^5x=-6

x=-6/1

x=-6

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